4x-1/x^2-3=0

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Solution for 4x-1/x^2-3=0 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

4*x-(1/(x^2))-3 = 0

4*x-x^-2-3 = 0

4*x^1-1*x^-2-3*x^0 = 0

(4*x^3-3*x^2-1*x^0)/(x^2) = 0 // * x^4

x^2*(4*x^3-3*x^2-1*x^0) = 0

x^2

4*x^3-3*x^2-1 = 0

{ 1, -1 }

1

x = 1

4*x^3-3*x^2-1 = 0

1

x-1

4*x^2+x+1

4*x^3-3*x^2-1

x-1

4*x^2-4*x^3

x^2-1

x-x^2

x-1

1-x

0

4*x^2+x+1 = 0

DELTA = 1^2-(1*4*4)

DELTA = -15

DELTA < 0

x in { 1} 

x = 1

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